0.25x^2+x-80=0

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Solution for 0.25x^2+x-80=0 equation: 



0.25x^2+x-80=0

a = 0.25; b = 1; c = -80;
Δ = b2-4ac
Δ = 12-4·0.25·(-80)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-9}{2*0.25}=\frac{-10}{0.5}
=-20
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+9}{2*0.25}=\frac{8}{0.5}
=16
$

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